3.2x+-2x^2-5=0

Solution for 3.2x+-2x^2-5=0 equation:

3.2x+-2x^2-5=0

We add all the numbers together, and all the variables

-2x^2+3.2x=0

a = -2; b = 3.2; c = 0;
Δ = b2-4ac
Δ = 3.22-4·(-2)·0
Δ = 10.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{10.24}}{2*-2}=\frac{-3.2-\sqrt{10.24}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{10.24}}{2*-2}=\frac{-3.2+\sqrt{10.24}}{-4}
$